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Extract string based on regex pattern

Source: R/str_extract.R
str_extract.Rd

Use base::strsplit to

Usage

str_extract(d, pattern)

Arguments

d

vector of character strings

pattern

regex pattern to match

Value

vector of character strings

Examples

ls <- do.call(c,lapply(sample(4:8,20,TRUE),function(i){
paste(sample(letters,i,TRUE),collapse = "")}))
ds <- do.call(c,lapply(1:20,function(i){
paste(sample(ls,1),i,sample(ls,1),"23",sep = "_")}))
str_extract(ds,"([0-9]+)")
#>  [1] "1"  "2"  "3"  "4"  "5"  "6"  "7"  "8"  "9"  "10" "11" "12" "13" "14" "15"
#> [16] "16" "17" "18" "19" "20"
str_extract("34 (30 %)","^\\d+")
#> [1] "34"